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Question Answer
(a + b) 2 = a2 + 2ab + b2.
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(a + b) 2 = a2 + 2ab + b2.
suma kwadratów
(a − b) 2 = a2 − 2ab + b2
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(a - b) 2 = a2 - 2ab + b2
kwadrat różnicy
a2 − b2 = (a − b)(a + b)
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a2 - b2 = (a - b) (a + b)
różnica kwadratów
f(x)=a(x−p) 2+q
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f (x) = a (x - p) 2 + q
postac kanoniczna
f(x)=ax2+bx+c
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f (x) = ax2 + bx + c
postac ogólna
∆=b2-4×a×c
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∆ = b2-4 × a × c
obliczanie delty

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