wzory trygonometryczne - fiszki

 0    28 flashcards    vautreimoufeicri2949
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Question język polski Answer język polski
sin(α+β)=
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sinα • cosβ + sinβ • cosα
sin(α-β)=
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sinα • cosβ - sinβ • cosα
cos(α+β)=
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cosα • cosβ - sinα • sinβ
cos(α-β)=
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cosα • cosβ + sinα • sinβ
tg(α+β)=
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tgα + tgβ / 1 - tgα • tgβ
tg(α-β)=
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tgα - tgβ / 1 + tgα • tgβ
ctg(α+β)=
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ctgα • ctgβ - 1 / ctgβ + ctgα
ctg(α-β)=
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ctgα • ctgβ + 1 / ctgβ - ctgα
sin 2α=
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2 • sinα • cosα
cos 2α=
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cos²α - sin²α
cos 2α=
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2cos²α - 1
cos 2α=
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1 - 2sin²α
cos²α - sin²α=
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2cos²α - 1
cos²α - sin²α=
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1 - 2sin²α
2cos²α - 1=
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1 - 2sin²α
tg 2α=
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2 tgα / 1 - tg²α
ctg 2α=
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ctg²α - 1 / 2 ctgα
sinα + sinβ=
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2 sin (α + β / 2) • cos (α - β / 2)
sinα - sinβ=
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2 sin (α - β / 2) • cos (α + β / 2)
cosα + cosβ=
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2 cos (α + β / 2) • cos (α - β / 2)
cosα - cosβ=
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- 2 sin (α + β / 2) • sin (α - β / 2)
tgα + tgβ=
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sin (α + β) / cosα • cosβ
tgα - tgβ=
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sin (α - β) / cosα • cosβ
ctgα + ctgβ=
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sin (β + α) / sinα • sinβ
ctgα - ctgβ=
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sin (β - α) / sinα • sinβ
sin α • cos β =
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sin(α+β) + sin(α-β) / 2
cos α • cos β =
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cos (α+β) + cos (α-β) / 2
sin α • sin β =
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cos (α-β) - cos (α+β) / 2

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