równania kwadratowe

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Question język polski Answer język polski
f(x) =
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ax^2 + bx + c = 0
delta =
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b^2 - 4ac
delta > 0
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x1 = (-b - √Δ)/2a x2 = (-b + √Δ)/2a
delta = 0
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x = -b/2a
delta < 0
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delta < 0 in Polish
nie ma rozwiązania

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