funkcje wzory

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Question Answer
(c)'
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(c) ' = 0
(x^n)'=
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(x^n)'= nx^n-1
(a/x)'
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(a/x)'=- a/x²
(e^x)
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(e^x)= e^x
(ln x)'
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(ln x)'= 1/x
(log↓a x)'
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(log↓ax)'= 1/x•ln a
(a^x)'
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(a^x) '= a^x• ln a
(sin x)'
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(sin x)'= cos x
(cos x)'
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(cos x)'=- sin x
(tg x)'
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(tg x)' = 1/cos²x
(ctg x)'
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(ctg x)'= -1/sin²x
(√x)'
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(√x)' = 1/2√x
(x)'
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(x) '= 1

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